HappyTheSkibidi
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- Aug 31, 2025
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- HSC
- 2025
only 1 cause OH uses up the mg needed to ppt co3i said both will ppt but i don’t think thats right LOL
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only 1 cause OH uses up the mg needed to ppt co3i said both will ppt but i don’t think thats right LOL
I'm pretty sure it's Dngl i did that in the start i completely forgot and i’m like lowkey out of it rn so i don’t remember![]()
magnesiuk hydroxide and another one will ppt right? i js found the qsp and showed its more than ksp and therforr it ppptedi said both will ppt but i don’t think thats right LOL
oh i thought there was still Mg+ left after that bc i found molar solubility and subtracted rhat from mg+ added so idkonly 1 cause OH uses up the mg needed to ppt co3
Cause I accidentally did it the other way around all my steps were right but it was for pOHfor the Ka x Kb question, I accidentally did N2H4 + H2O —> OH- + N2H5+ so I got POH as like 4.46. How many marks would I lose for this
yeah samemagnesiuk hydroxide and another one will ppt right? i js found the qsp and showed its more than ksp and therforr it pppted
checking with others its probably cI'm pretty sure it's D
We increase the volume by a factor of two which means concentration decreases no?
I didnt sit this years HSC but im pretty sure the markers are looking for you to use the initial pH of 2.5 rather than trying to identify the half equivalence point and the corresponding pH since this may be more inaccurateFor a weak acid u look at the 1/2 equivalence point where pH=pKa, then solve for Ka
Because for 13pH to happen the conc of OH- has to be 0.1mol/L which can’t occur since some of the OH- is neutralised by the H+ from the weak acid.
its only 1i said both will ppt but i don’t think thats right LOL
so was ph 4.46 ?? and you wrote poh??Cause I accidentally did it the other way around all my steps were right but it was for pOH
oh whatI didnt sit this years HSC but im pretty sure the markers are looking for you to use the initial pH of 2.5 rather than trying to identify the half equivalence point and the corresponding pH since this may be more inaccurate
i got same though 85.7% i think its righti kinda got 85.7% but fudged it and made it 85.5%
why did i do that AAHHHH
2-methyl but-2-eneDid y’all get 2methylbut2ene or 2methylbutene for the last question
Nevermind you're right lmaochecking with others its probably c
Im not saying you will lose marks for it, its just probably what they wanted + its probably the easiest/most straightforward way to do the questionoh what![]()
No like o did the equation for dissociation of base instead of the acid by accidentso was ph 4.46 ?? and you wrote poh??
Wait so it’s one?? I said it will preferentially ppt with OH- first so I did Ksp calculation and check the remaining OH- available for Co32- and if ppt can occur with thatonly 1 cause OH uses up the mg needed to ppt co3
i said MgOH2 will ppt first since Ksp is lower, and then did the calc for that. Then the left over Mg wasnt enough to form ppt with MgCO3 using Qsp < Ksp but idk if i was right or just gaslighting myselfWait so it’s one?? I said it will preferentially ppt with OH- first so I did Ksp calculation and check the remaining OH- available for Co32- and if ppt can occur with that
I did the calculation and there is enough excess Mg2+ to precipitate with both the carbonate and hydroxide ions. I said 2.Wait so it’s one?? I said it will preferentially ppt with OH- first so I did Ksp calculation and check the remaining OH- available for Co32- and if ppt can occur with that
