2024 HSC Chat (9 Viewers)

C_master · Jan 17, 2024

WeiWeiMan said:
Summing the digits of 2024 yields:
2+0+2+4=8
Rotating 8 by 90˚ yields the infinity symbol
What is Gojo's Technique?
INFINITY
What does this mean?
Gojo is coming back in 2024

stop gatekeeping plz

whats the recent obsession with gatekeeping

Aeonium · Jan 17, 2024

WeiWeiMan said:
Summing the digits of 2024 yields:
2+0+2+4=8
Rotating 8 by 90˚ yields the infinity symbol
What is Gojo's Technique?
INFINITY
What does this mean?
Gojo is coming back in 2024

stop gatekeeping plz

if you can get rid of intellectual property/copyright as a concept within society i will

yolo tengo · Jan 17, 2024

WeiWeiMan said:
Summing the digits of 2024 yields:
2+0+2+4=8
Rotating 8 by 90˚ yields the infinity symbol
What is Gojo's Technique?
INFINITY
What does this mean?
Gojo is coming back in 2024

stop gatekeeping plz

keep on dreaming, my glorious blue eyed king will not come back

C_master · Jan 17, 2024

C_master · Jan 17, 2024

Ace chill I so wanted to go out today

its_ace21 · Jan 17, 2024

C_master said:
Ace chill I so wanted to go out today

tomrw is sunny i think

bananaa3 · Jan 17, 2024

ziGma said:
Quick question just for my general knowledge - How many of ya'll are tutored or used to do tutoring for during senior years?

Majority of the people in my cohort take tutoring (although many deny it) and I think it's the main reason they excel. Although I haven't done tutoring for any senior subjects, I was wondering how many people here, do tutoring and whether it helps...

Bonus Q - Do you tell your peers/friends/teachers about taking tutoring or 'hide' it?

i did online tutoring for a while but i don't think it really helped, i wish i could do some in person tutoring (idk i think it works better than online tutoring) and yeah i told my friends that i did online tutoring, i don't understand why some people try to hide it tho

C_master · Jan 17, 2024

its_ace21 said:
tomrw is sunny i think

Better be

C_master · Jan 17, 2024

bananaa3 said:
i did online tutoring for a while but i don't think it really helped, i wish i could do some in person tutoring (idk i think it works better than online tutoring) and yeah i told my friends that i did online tutoring, i don't understand why some people try to hide it tho

Why can't you do in person?

Aeonium · Jan 18, 2024

just questioning if i can skip the $\frac{du}{dx} = -5 \,\rightarrow\, dx = -\frac{du}5$ and just say $u = 1-5x \,\rightarrow\, dx = -\frac{du}5$ bcz i'm too ceebs to write it all out
$\begin{align*} \int\,&\frac{1}{\left(1-5x\right)^3}\,dx\\ \text{Let } u&=1-5x\\ \frac{du}{dx}&=-5\\ \implies dx&=-\frac{du}{5}\\ \int\,\frac{1}{\left(1-5x\right)^3}\,dx&=-\int\,u^{-3}\,\frac{du}{5}\\ &=-\frac{1}{5}\int u^{-3}\,du\\ &=-\frac{1}{5}\left(\frac{u^{-2}}{2}\right) + C\\ &=-\left(-\frac{u^{-2}}{10}\right)+C\\ &=\frac{1}{10\left(1-5x\right)^2}+C \end{align*}$

WeiWeiMan · Jan 18, 2024

Aeonium said:
just questioning if i can skip the $\frac{du}{dx} = -5 \,\rightarrow\, dx = -\frac{du}5$ and just say $u = 1-5x \,\rightarrow\, dx = -\frac{du}5$ bcz i'm too ceebs to write it all out
$\begin{align*} \int\,&\frac{1}{\left(1-5x\right)^3}\,dx\\ \text{Let } u&=1-5x\\ \frac{du}{dx}&=-5\\ \implies dx&=-\frac{du}{5}\\ \int\,\frac{1}{\left(1-5x\right)^3}\,dx&=-\int\,u^{-3}\,\frac{du}{5}\\ &=-\frac{1}{5}\int u^{-3}\,du\\ &=-\frac{1}{5}\left(\frac{u^{-2}}{2}\right) + C\\ &=-\left(-\frac{u^{-2}}{10}\right)+C\\ &=\frac{1}{10\left(1-5x\right)^2}+C \end{align*}$

na
u could write it like:
x=-u/5
\therefore dx=-du/5

Average Boreduser · Jan 18, 2024

Aeonium said:
just questioning if i can skip the $\frac{du}{dx} = -5 \,\rightarrow\, dx = -\frac{du}5$ and just say $u = 1-5x \,\rightarrow\, dx = -\frac{du}5$ bcz i'm too ceebs to write it all out
$\begin{align*} \int\,&\frac{1}{\left(1-5x\right)^3}\,dx\\ \text{Let } u&=1-5x\\ \frac{du}{dx}&=-5\\ \implies dx&=-\frac{du}{5}\\ \int\,\frac{1}{\left(1-5x\right)^3}\,dx&=-\int\,u^{-3}\,\frac{du}{5}\\ &=-\frac{1}{5}\int u^{-3}\,du\\ &=-\frac{1}{5}\left(\frac{u^{-2}}{2}\right) + C\\ &=-\left(-\frac{u^{-2}}{10}\right)+C\\ &=\frac{1}{10\left(1-5x\right)^2}+C \end{align*}$

alternatively u can skip like 8 of those lines if u consider 1-5x as x

WeiWeiMan · Jan 18, 2024

Aeonium said:
just questioning if i can skip the $\frac{du}{dx} = -5 \,\rightarrow\, dx = -\frac{du}5$ and just say $u = 1-5x \,\rightarrow\, dx = -\frac{du}5$ bcz i'm too ceebs to write it all out
$\begin{align*} \int\,&\frac{1}{\left(1-5x\right)^3}\,dx\\ \text{Let } u&=1-5x\\ \frac{du}{dx}&=-5\\ \implies dx&=-\frac{du}{5}\\ \int\,\frac{1}{\left(1-5x\right)^3}\,dx&=-\int\,u^{-3}\,\frac{du}{5}\\ &=-\frac{1}{5}\int u^{-3}\,du\\ &=-\frac{1}{5}\left(\frac{u^{-2}}{2}\right) + C\\ &=-\left(-\frac{u^{-2}}{10}\right)+C\\ &=\frac{1}{10\left(1-5x\right)^2}+C \end{align*}$

as average boreduser said (kinda), your working is hella unnecessary
u can rewrite it as like

$\begin{align*} \int \frac{1}{(1-5x)^3} \text dx &=\int (1-5x)^{-3} \text dx \\ &= \(1-5x)^{-2} \cdot \frac{1}{-2} \cdot \frac{1}{-5} + C \\ &= \frac{1}{10(1-5x)^2} + C \end{align*}$

Average Boreduser said:
alternatively u can skip like 8 of those lines if u consider 1-5x as x

Aeonium · Jan 18, 2024

Average Boreduser said:
alternatively u can skip like 8 of those lines if u consider 1-5x as x

as u you mean ?

Aeonium · Jan 18, 2024

WeiWeiMan said:
as average boreduser said (kinda), your working is hella unnecessary
u can rewrite it as like

$\begin{align} \int \frac{1}{(1-5x)^3} \ text dx &=\int (1-5x)^{-3} \text dx \\ &= \(1-5x)^{-2} \cdot \frac{1}{-2} \cdot \frac{1}{-5} + C \\ &= \frac{1}{10(1-5x)^2} + C \end{align}$

uh the qn asked for substitution (sorry should've clarified)

Average Boreduser · Jan 18, 2024

Aeonium said:
uh the qn asked for substitution (sorry should've clarified)

oh fair enough then

mb

Aeonium · Jan 18, 2024

Average Boreduser said:
oh fair enough then mb

naw it's my bad i should've clarified in the start

Cute-Duckie · Jan 18, 2024

Aeonium said:
currently
View attachment 42158 View attachment 42159
the plan is to import the average mark from each individual sheet to the 'Analytics' sheet –> colour indicator if your average is meeting your goals or not as well as the other pages but this requires making custom scripts
this is most definitely not a good use of my time but it's fine it's motivation woops the reds are mismatched i hate selecting in colour palettes

woah this is so cool can you make like a blank copy and share it with eveyrone when you're done?? this seems super useful

Aeonium · Jan 19, 2024

Cute-Duckie said:
woah this is so cool can you make like a blank copy and share it with eveyrone when you're done?? this seems super useful

i think i'm pretty far from finishing it tho but i probably will

Cathode_RT · Jan 19, 2024

damn the 2023 stuff got archived

good luck you 2024 youngins

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I'm so done with trimesters bruh

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